An object with a mass of # 6 kg# is lying still on a surface and is compressing a horizontal spring by #3/4 m#. If the spring's constant is # 8 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

Question

1474 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-25T01:57:33

coefficient of static friction(#mu#)#=0.0375#

At equilibrium, force exerted by spring on object is balanced by force of friction.
So,
#1/2kx^2=mumg#

substituting #k=8kgs^(-2) , x=3/4m , m=6kg and g=10ms^(-2)# , we get #mu = 0.0375#