# An object with a mass of #6 kg# is on a surface with a kinetic friction coefficient of # 8 #. How much force is necessary to accelerate the object horizontally at # 19 m/s^2#?

##### 1 Answer

Nov 17, 2016

#### Answer:

# 584.4 N#

#### Explanation:

The forces are marked on the diagram;

#F = # Friction

#R = # Reaction from the surface

#D = # Driving Force (our unknown)

Applying NSL vertically downwards:

# 6g - R = 0 #

# :. R = 6g #

# :. R = 58.8N #

Applying NSL horizontally:

# D - F = (6)(19) #

# :. D = 114 + F #

# :. D = 114 + muR #

# :. D = 114 + (8)(58.8) #

# :. D = 114 + 470.4 #

# :. D = 584.4 N#