An object with a mass of #6 kg# is revolving around a point at a distance of #2 m#. If the object is making revolutions at a frequency of #9 Hz#, what is the centripetal force acting on the object?

1 Answer
Dec 30, 2015

Answer:

I found #~~38kN#

Explanation:

We have that centripetal force is:
#F_c=ma_c=mv^2/r#
Where:
#v=("distance")/("time")=("circumference")/("period")=(2pir)/T#
With: #T=1/("frequency")=1/9#
So:
#v=2*3.14*2*9=113.04m/s#
So:
#F_c=6*(113.04)^2/2=38,334N#