An object with a mass of #6 kg# is revolving around a point at a distance of #4 m#. If the object is making revolutions at a frequency of #1 Hz#, what is the centripetal force acting on the object?

1 Answer
Feb 8, 2016

Answer:

#F_c=48*pi#

Explanation:

#"The centripetal force is given by formula :" F_c=m*v^2/r#
#"we can write: " v=omega*r #
#F_c=m*omega^2*r^2/r#
#F_c=m*omega^2*r#
#omega=2*pi*f#
#F_c=6*2*pi*1*4#
#F_c=48*pi#