An object with a mass of #6 kg# is revolving around a point at a distance of #8 m#. If the object is making revolutions at a frequency of #3 Hz#, what is the centripetal force acting on the object?

1 Answer
May 3, 2016

Answer:

#17037.4N#

Explanation:

The centripetal force acting on an object of massm,revolving round a circular path of radius r with frequency n is given by

#F_c=m*4(pin)^2*r=6*4(3.14*3)^2*8=17037.4N#