An object with a mass of $6 k g$ $6 kg$ is revolving around a point at a distance of $8 m$ $8 m$ . If the object is making revolutions at a frequency of $5 H z$ $5 Hz$ , what is the centripetal force acting on the object?

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An object with a mass of $6 k g$ $6 kg$ is revolving around a point at a distance of $8 m$ $8 m$ . If the object is making revolutions at a frequency of $5 H z$ $5 Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2016-01-31T02:18:19

The centripetal force is given by $F = m ω^{2} r$ $F=momega^2r$ and is $4800 π^{2}$ $4800pi^2$ $N$ $N$ or $47, 374$ $47,374$ $N$ $N$

Explanation:

The centripetal acceleration is given by:

$a = ω^{2} r$ $a=omega^2r$

Where:

$r$ $r$ is the radius $(m)$ $(m)$
$ω$ $omega$ is the rotational speed $(r a d s^{- 1})$ $(rads^-1)$

we were given the rotational frequency in $H z$ $Hz$ (cycles per second), and there are $2 π$ $2pi$ radians in a cycle, so to find the rotational speed multiply $5$ $5$ $H z$ $Hz$ by $2 π$ $2pi$ to give $10 π$ $10pi$ $r a d s^{- 1}$ $rads^-1$ .

Using Newton's Second Law , the centripetal force will be $m$ $m$ times the centripetal acceleration.

$F = m a = m ω^{2} r = 6 \cdot {(10 π)}^{2} \cdot 8 = 4800 π^{2} N = 47, 374 N$ $F = ma = momega^2r = 6*(10pi)^2*8 = 4800pi^2 N = 47,374 N$

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An object with a mass of $6 k g$ $6 kg$ is revolving around a point at a distance of $8 m$ $8 m$ . If the object is making revolutions at a frequency of $5 H z$ $5 Hz$ , what is the centripetal force acting on the object?

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Explanation:

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Science

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An object with a mass of 6kg6 kg is revolving around a point at a distance of 8m8 m. If the object is making revolutions at a frequency of 5Hz5 Hz, what is the centripetal force acting on the object?

1 Answer

Explanation:

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An object with a mass of $6 k g$ $6 kg$ is revolving around a point at a distance of $8 m$ $8 m$ . If the object is making revolutions at a frequency of $5 H z$ $5 Hz$ , what is the centripetal force acting on the object?