An object with a mass of #6 kg# is revolving around a point at a distance of #8 m#. If the object is making revolutions at a frequency of #5 Hz#, what is the centripetal force acting on the object?

1 Answer
Jan 31, 2016

Answer:

The centripetal force is given by #F=momega^2r# and is #4800pi^2# #N# or #47,374# #N#

Explanation:

The centripetal acceleration is given by:

#a=omega^2r#

Where:

#r# is the radius #(m)#
#omega# is the rotational speed #(rads^-1)#

we were given the rotational frequency in #Hz# (cycles per second), and there are #2pi# radians in a cycle, so to find the rotational speed multiply #5# #Hz# by #2pi# to give #10pi# #rads^-1#.

Using Newton's Second Law , the centripetal force will be #m# times the centripetal acceleration.

#F = ma = momega^2r = 6*(10pi)^2*8 = 4800pi^2 N = 47,374 N#