An object with a mass of #7 kg# is lying still on a surface and is compressing a horizontal spring by #5 /8 m#. If the spring's constant is #16 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2017-04-26T07:53:57

The coefficient of static friction is #=0.15#

The force of friction is

#F_r=k*Deltax#

The spring constant is #k=16kgs^-2#

The distance is #Deltax=5/8m#

Therefore,

#F_r=16*5/8=10N#

The coefficient of static friction is

#mu_s=F_r/N#

The normal force is #N=mg=(7g) N#

So,

#mu_s=(10)/(7g)=0.15#