An object with a mass of #7 kg# is on a surface with a kinetic friction coefficient of # 7 #. How much force is necessary to accelerate the object horizontally at #2 m/s^2#?

1 Answer
ali ergin
Mar 14, 2016

#F=494,69 " "N#

Explanation:

#G=m*g=7*9,81=68,67 N" gravity of object"#
#N=-G" normal force to the contacting surfaces"#
#F_f=k*N=7*68,67=480,69N #
#"The friction force for contacting surfaces"#
#F_"net"=m*a" The Newton's second law"#
#F_"net"=F-F_f#
#F-F_f=m*a#
#F-480,69=7*2#
#F-480,69=14#
#F=480,69+14#
#F=494,69 " "N#

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