# An object with a mass of 7 kg is on a surface with a kinetic friction coefficient of  8 . How much force is necessary to accelerate the object horizontally at  12 m/s^2?

Net force =${F}_{n} = m \times a = 7 k g \times 12 \frac{m}{s} ^ 2 = 84 N$
Frictional force = ${F}_{F} = \mu m g = 3 \times 7 k g \times 9.8 \frac{m}{s} ^ 2 = 205.8 N$
So the applied force to have necessary acceleration ${F}_{a p p} = {F}_{n} + {F}_{F} = 84 + 205.8 = 289.8 N$