An object with a mass of #7 kg# is on a surface with a kinetic friction coefficient of # 8 #. How much force is necessary to accelerate the object horizontally at # 12 m/s^2#?

1 Answer
P dilip_k
Apr 16, 2016

Net force =#F_n=mxxa=7kgxx12m/s^2= 84 N#
Frictional force = #F_F=mumg=3xx7kgxx9.8m/s^2=205.8N#
So the applied force to have necessary acceleration #F_(app)=F_n+F_F=84+205.8=289.8N#

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