An object with a mass of #7 kg# is pushed along a linear path with a kinetic friction coefficient of #u_k(x)= 1-cos(x/6) #. How much work would it take to move the object over #x in [0, 8pi], where x is in meters?

1 Answer
Jan 4, 2018

The work is #=2078.6J#

Explanation:

#"Reminder : "#

#intcosaxdx=1/asinax+C#

The work done is

#W=F*d#

The frictional force is

#F_r=mu_k*N#

The coefficient of kinetic friction is #mu_k=(1-cos(x/6))#

The normal force is #N=mg#

The mass of the object is #m=7kg#

#F_r=mu_k*mg#

#=7*(1-cos(x/6))g#

The work done is

#W=7gint_(0)^(8pi)(1-cos(x/6))dx#

#=7g*[x-6sin(1/6x)]_(0)^(8pi)#

#=7g(8pi-6sin(4/3pi)-(0))#

#=7g(30.3)#

#=2078.6J#