An object with a mass of #8 kg# is lying still on a surface and is compressing a horizontal spring by #5/6 m#. If the spring's constant is #1 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

1 Answer
Jun 20, 2017

Answer:

The coefficient of static friction is #=0.011#

Explanation:

The coefficient of static friction is

#mu_s=F_r/N#

#F_r=k*x#

The spring constant is #k=1kgs^-2#

The compression is #x=5/6m#

Therefore,

#F_r=1*5/6=0.83N#

The normal force is

#N=mg=8gN#

The coefficient of static friction is

#mu_s=(0.83)/(8g)=0.011#