# At how many revolutions per minute the ride should spin in order for the rider to feel a centripetal acceleration of about 1.5 times Earth’s gravitational acceleration?

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A flying-saucer shaped fairground ride is rotating in a horizontal plane. If the rider’s circular path has a radius of 8 m

R = 8m

A flying-saucer shaped fairground ride is rotating in a horizontal plane. If the rider’s circular path has a radius of 8 m

R = 8m

##### 1 Answer

#### Answer:

#### Explanation:

For circular motion the magnitude of the centripetal force on an object of mass

#F=ma_{c}=\frac {mv^{2}}{r}# ......(1)

where#a_c# is the centripetal acceleration.

The angular velocity

#v = romega# and

#omega=2pif#

where#f# is frequency in number of cycles per second.

So that

We are required to find

Solving (3) for