# At room temperature, an oxygen molecule, with mass of 5.31 x 10^-26 kg, typically has a KE of about 6.21 x 10-21 J. How fast is the molecule moving?

Jul 18, 2017

#### Answer:

$484 m {s}^{- 1}$

#### Explanation:

${E}_{k} = \frac{m {v}^{2}}{2} = 6.21 \cdot {10}^{- 21} J$

$6.21 \cdot {10}^{- 21} = \frac{5.31 \cdot {10}^{- 26} {v}^{2}}{2}$

$v = \sqrt{\frac{2 \left(6.21 \cdot {10}^{- 21}\right)}{5.31 \cdot {10}^{- 26}}} = 483.630339 \approx 484 m {s}^{- 1}$