Boric acid can take only one electron pair due to absence of d orbital.What does this means?

1 Answer
Nov 19, 2017

The valence shell of a boron atom is the second shell, which does not include #d#-orbitals. More explanation follows...

Explanation:

Remember that the electron configuration of boron is #1s^2 2s^2 2p^1#

The boron atom at the centre of the boric acid molecule (see the diagram) is covalently bonded to each of three oxygen atoms, using #sp^2# bonding, involving three of the four valence orbitals.

upload.wikimedia.org/wikipedia/commons/thumb/4/4a/Boric-acid-2Dpng/100px-Boric-acid-2Dpng

This leaves one empty orbital in the valence shell of the boron atom, and makes it possible for the molecule to gain an electron pair by forming a "coordinate covalent bond" with another particle that has a lone pair (a full, unbonded orbital) in its valence shell.

However, because the boron atom's valence shell is the second shell, and consists of only #s#- and #p#-orbitals, it does not possess any #d#-orbitals (which come into existence at n=3 (the third shell).
Additional #d#-orbitals would allow for more electron pairs to be added, but these do not exist in the structure of a boron atom.