At a constant temperature, a gas that exerted a pressure of 1.47 atm and that occupied 1.62 L is compressed until its pressure is 7.42 am. What is the final volume?

1 Answer
May 17, 2018

"0.32 L"0.32 L

Explanation:

From Boyle’s Law

"P"_1"V"_1 = "P"_2"V"_2P1V1=P2V2

"V"_2 = ("P"_1"V"_1)/("P"_2) = (1.47 cancel"atm" × "1.62 L")/(7.42 cancel"atm") = "0.32 L"