# At a constant temperature, a gas that exerted a pressure of 1.47 atm and that occupied 1.62 L is compressed until its pressure is 7.42 am. What is the final volume?

$\text{0.32 L}$
${\text{P"_1"V"_1 = "P"_2"V}}_{2}$
$\text{V"_2 = ("P"_1"V"_1)/("P"_2) = (1.47 cancel"atm" × "1.62 L")/(7.42 cancel"atm") = "0.32 L}$