#### Explanation:

Let us assume Filmon paid $x and therefore Petros paid $(x+80).

So two together paid $x+$(x+80) i.e. $(2x+80). Hence, Yonas paid $(2x+80)+$220=$2x+300, which was $480 more than Petros, who had paid $(x+80) i.e.

$2 x + 300 = x + 80 + 480 = x + 560$

Hence, $2 x - x = 560 - 300$ or $x = 260$.

Hence Filmon paid $260 Petros paid $260+$80=$340 and

Yonas paid $(2xx260+300)=$(520+300)=$820 Hence, present costs $2360+$340+$820=$1420 Sep 26, 2016 $1420" " was the cost of the present.

#### Explanation:

Before we can start comparing how much each spent, we need to define a variable to use.
Filmon paid the least.

Let the amount Filmon paid be $x$

Write an expression for how much each of them paid, in terms of $x$

Filmon paid: $x \text{ }$ Petros paid $80 more: $x + 80$Yonas paid $220$more than both together: Yonas: $\left(x + x + 80\right) + 220 = 2 x + 300$The difference between Yonas' and Petros' payments is$480

"(biggest - smaller" = $480) $2 x + 300 - \left(x + 80\right) = 480$$2 x + 300 - x - 80 = 480$$x = 480 - 300 + 80$x =$260

Filmon paid $260 Petros paid: 260+80 =$340
Yonas paid 2 xx 260+300 =$820 The cost of the present was: $260+$340+$820

\$1420