# Calcium chloride is often used to de-ice roads in the winter. What volume would 15.7 g calcium chloride occupy, if the density is 2.50 g/cm^3?

By definition, $\rho , \text{density"="mass"/"volume}$
And so $\frac{\text{volume"="mass}}{\rho} = \frac{15.7 \cdot g}{2.50 \cdot g \cdot c {m}^{-} 3} = 6.3 \cdot g \cdot c {m}^{3}$...
$\frac{g}{g \cdot c {m}^{-} 3} = \frac{\cancel{g}}{\cancel{g} \cdot \frac{1}{c {m}^{3}}} \equiv c {m}^{3}$...a unit of volume as required....