Calcium chloride is often used to de-ice roads in the winter. What volume would #15.7# #g# calcium chloride occupy, if the density is #2.50# #g##/cm^3#?

1 Answer
anor277
Mar 15, 2018

By definition, #rho,"density"="mass"/"volume"#

Explanation:

And so #"volume"="mass"/rho=(15.7*g)/(2.50*g*cm^-3)=6.3*g*cm^3#...

And note that is dimensionally consistent given that...

#g/(g*cm^-3)=cancelg/(cancelg*1/(cm^3))-=cm^3#...a unit of volume as required....

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