Consider two vectors A=3i - 1j and B = - i - 5j, how do you calculate abs(A-B)?

Dec 9, 2015

$| A - B | = \sqrt{32}$

Explanation:

$A - B = A + \left(- B\right)$

$= 3 \hat{i} - \hat{j} + \left(\hat{i} + 5 \hat{j}\right)$

$= 4 \hat{i} - 4 \hat{j}$

$\therefore | A - B | = | 4 \hat{i} - 4 \hat{j} |$

$= \sqrt{{4}^{2} + {4}^{2}}$

$= \sqrt{32}$