# Container A holds 737 mL of ideal gas at 2.30 atm. Container B holds 114 mL of ideal gas at 4.40 atm. lf the gases are allowed to mix together, what is the resulting pressure?

##### 1 Answer

The resulting pressure is 2.58 atm.

#### Explanation:

According to **Dalton's Law of Partial Pressures**, each gas will exert its pressure independently of the other.

Hence we can use **Boyle's Law** to calculate the pressure of each gas separately as it expands into the total volume of the two containers.

**Calculate the pressure of Gas A**

Boyle's Law is

#color(blue)(bar(ul(|color(white)(a/a)p_1V_1 = p_2V_2color(white)(a/a)|)))" "#

**Calculate the pressure of Gas B**

**Calculate the total pressure**

The formula for Dalton's Law of Partial Pressures is

#color(blue)(bar(ul(|color(white)(a/a)p_"tot" = p_"A" + p_"B"color(white)(a/a)|)))" "#