Describe all 4 quantum numbers for last electron of 3d^5?

2 Answers
Jun 6, 2018

Answer:

see below

Explanation:

it is Mn (manganese)
N= 3 third energetic level
l= 3 shape of orbitals of type d : (quatrefoil)
5 = the 5 orbitals d are all full means with only one electron in every orbitals (M,magnetic orbitatals = -2,-1, 0 +1 +2 what is the last, you don't know because are isoenergetic)
s =intrinsic magnetic moment #= +- h/(2 xx pi)#(what is the last, you don't know, for convention the negative one)

Jun 6, 2018

Answer:

The four quantum numbers are 3, 2, +2, +½.

Explanation:

The four quantum numbers are

  • #n color(white)(ll)=# principal quantum number; determines energy and size of orbital
  • #l color(white)(m)= # secondary quantum number; determines shape of orbital
  • #m_text(l) =#magnetic quantum number; determines orientation of orbital in magnetic field
  • #m_text(s) =# spin quantum number; determines direction of electron spin

The rules for quantum numbers are:

  • #n color(white)(ll)=# integers from 1 to ∞.
  • #lcolor(white)(m)= # integers from 0 to #n - 1#
  • #m_text(l) =# integers from #-l# to #+l#
  • #m_text(s) =# +½ or -½

Here is a table of quantum numbers for the first five #"3d"# electrons. The quantum numbers for the fifth electron are red.

#ulbb(ncolor(white)(m)lcolor(white)(ml)m_text(l)color(white)(ml)m_text(s))#
#3color(white)(m)2color(white)(mll)"-2"color(white)(m)"+½#
#3color(white)(m)2color(white)(mll)"-1"color(white)(m)"+½#
#3color(white)(m)2color(white)(mm)"0"color(white)(m)"+½#
#3color(white)(m)2color(white)(m)"+1"color(white)(m)"+½#
#color(red)(3color(white)(m)2color(white)(m)"+2"color(white)(m)"+½)#

Here's how the quantum numbers fit in the Periodic Table

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