# Describe all 4 quantum numbers for last electron of 3d^5?

##### 2 Answers

#### Answer:

see below

#### Explanation:

it is Mn (manganese)

N= 3 third energetic level

l= 3 shape of orbitals of type d : (quatrefoil)

5 = the 5 orbitals d are all full means with only one electron in every orbitals (M,magnetic orbitatals = -2,-1, 0 +1 +2 what is the last, you don't know because are isoenergetic)

s =intrinsic magnetic moment

#### Answer:

The four quantum numbers are 3, 2, +2, +½.

#### Explanation:

The four quantum numbers are

#n color(white)(ll)=# **principal**quantum number; determines energy and size of orbital#l color(white)(m)= # **secondary**quantum number; determines shape of orbital#m_text(l) =# **magnetic**quantum number; determines orientation of orbital in magnetic field#m_text(s) =# **spin**quantum number; determines direction of electron spin

The rules for quantum numbers are:

#n color(white)(ll)=# integers from 1 to ∞.#lcolor(white)(m)= # integers from 0 to#n - 1# #m_text(l) =# integers from#-l# to#+l# #m_text(s) =# +½ or -½

Here is a table of quantum numbers for the first five

#ulbb(ncolor(white)(m)lcolor(white)(ml)m_text(l)color(white)(ml)m_text(s))#

#3color(white)(m)2color(white)(mll)"-2"color(white)(m)"+½#

#3color(white)(m)2color(white)(mll)"-1"color(white)(m)"+½#

#3color(white)(m)2color(white)(mm)"0"color(white)(m)"+½#

#3color(white)(m)2color(white)(m)"+1"color(white)(m)"+½#

#color(red)(3color(white)(m)2color(white)(m)"+2"color(white)(m)"+½)#

Here's how the quantum numbers fit in the Periodic Table