# Determine the density of chlorine gas at 22.0°C at 1 ATM?

Apr 27, 2017

Well, since $P V = n R T$, $\rho \cong 3 \cdot g \cdot {L}^{-} 1$

#### Explanation:

If $P V = n R T$ by the Ideal Gas equation, then.............

$\frac{P}{R T} = \frac{n}{V} = \frac{\text{mass"/"molar mass}}{V}$..........and

Thus, $\frac{P}{R T} \times \text{molar mass"="mass"/"volume"=rho, "i.e. density.}$

So thus $\rho = \frac{1 \cdot a t m \times 70.9 \cdot g \cdot m o {l}^{-} 1}{0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \times 295 \cdot K} = 2.93 \cdot g \cdot {L}^{-} 1$

$\text{Is the molar mass of chlorine gas correct? Why?}$