Determine the density of chlorine gas at 22.0°C at 1 ATM?

1 Answer
Apr 27, 2017

Answer:

Well, since #PV=nRT#, #rho~=3*g*L^-1#

Explanation:

If #PV=nRT# by the Ideal Gas equation, then.............

#P/(RT)=n/V=("mass"/"molar mass")/V#..........and

Thus, #(P)/(RT)xx"molar mass"="mass"/"volume"=rho, "i.e. density."#

So thus #rho=(1*atmxx70.9*g*mol^-1)/(0.0821*(L*atm)/(K*mol)xx295*K)=2.93*g*L^-1#

#"Is the molar mass of chlorine gas correct? Why?"#