Determine which law is appropriate for solving the following problem. What temperature will 215 mL of a gas at 20 C and 1 atm pressure attain when it is subject to 15 atm of pressure?

1 Answer
Jun 4, 2017

Answer:

#300^(@)# #"C"#

Explanation:

We must use the "combined gas law" #frac(P_(1) V_(1))(T_(1)) = frac(P_(2) V_(2))(T_(2))#.

In this case, the volume is kept constant, so #P_(1) = P_(2)#.

We can therefore cancel the terms from the equation:

#Rightarrow frac(V_(1))(T_(1)) = frac(V_(2))(T_(2))#

#Rightarrow frac(1 " atm")(20^(@) " C") = frac(15 " atm")(T_(2))#

Let's divide both sides of the equation by #15# #"atm"#:

#Rightarrow frac(1)(300^(@) " C") = frac(1)(T_(2))#

#Rightarrow (frac(1)(300^(@) " C"))^(- 1) = (frac(1)(T_(2)))^(- 1)#

#Rightarrow 300^(@)# #"C" = T_(2)#

#therefore T_(2) = 300^(@)# #"C"#

Therefore, the gas will attain a temperature of #300^(@)# #"C"# when it is subject to #15# #"atm"# of pressure.