how to solve this ???

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how to solve this ???

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Answer 1 · 2017-06-03T14:22:28

$a = 1, b = 2, c = 3, d = 4, e = 5, f = 6$ $a = 1, b = 2, c = 3, d = 4, e = 5, f = 6$

Explanation:

We have: $f (x) \equiv {(x - 2)}^{5} + 2 {(x - 2)}^{4} + 3 {(x - 2)}^{3} + 4 {(x - 2)}^{2} + 5 (x - 2) + 6$ $f(x) -= (x - 2)^(5) + 2 (x - 2)^(4) + 3 (x - 2)^(3) + 4 (x - 2)^(2) + 5 (x - 2) + 6$

Let's compare this to $f (x) \equiv a {(x - 2)}^{5} + b {(x - 2)}^{4} + c {(x - 2)}^{3} + d {(x - 2)}^{2} + e (x - 2) + f$ $f(x) -= a (x - 2)^(5) + b (x - 2)^(4) + c (x - 2)^(3) + d (x - 2)^(2) + e (x - 2) + f$ .

All we have to do is compare the coefficient of each term to $a, b, c, d, e$ $a, b, c, d, e$ and $f$ $f$

$\Rightarrow a = 1$ $Rightarrow a = 1$

$\Rightarrow b = 2$ $Rightarrow b = 2$

$\Rightarrow c = 3$ $Rightarrow c = 3$

$\Rightarrow d = 4$ $Rightarrow d = 4$

$\Rightarrow e = 5$ $Rightarrow e = 5$

$\Rightarrow f = 6$ $Rightarrow f = 6$

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