# how to solve this ???

Jun 3, 2017

$a = 1 , b = 2 , c = 3 , d = 4 , e = 5 , f = 6$

#### Explanation:

We have: $f \left(x\right) \equiv {\left(x - 2\right)}^{5} + 2 {\left(x - 2\right)}^{4} + 3 {\left(x - 2\right)}^{3} + 4 {\left(x - 2\right)}^{2} + 5 \left(x - 2\right) + 6$

Let's compare this to $f \left(x\right) \equiv a {\left(x - 2\right)}^{5} + b {\left(x - 2\right)}^{4} + c {\left(x - 2\right)}^{3} + d {\left(x - 2\right)}^{2} + e \left(x - 2\right) + f$.

All we have to do is compare the coefficient of each term to $a , b , c , d , e$ and $f$

$R i g h t a r r o w a = 1$

$R i g h t a r r o w b = 2$

$R i g h t a r r o w c = 3$

$R i g h t a r r o w d = 4$

$R i g h t a r r o w e = 5$

$R i g h t a r r o w f = 6$