# Exactly one mole of an ideal gas is contained in a 2.00 liter container at 1,000 K. What is the pressure exerted by this gas?

Over $40 \cdot a t m$. We follow the ideal gas equation
$P = \frac{n R T}{V}$ $=$ $\frac{1 \cdot \cancel{m o l} \times 0.0821 \cdot \cancel{L} \cdot a t m \cdot \cancel{{K}^{-} 1} \cdot \cancel{m o {l}^{-} 1} \times 1000 \cdot \cancel{K}}{2.00 \cdot \cancel{L}}$ $=$ ??*atm