Question

Find the area between the curve `y = e^(2x)` y = 0 from x = 1 to 3 ?

Answer 1

Area `= 1/2 (e^6-e^2) = 198.019868 ...`

Explanation:

The shaded are sought is given by the integral:

`A = int_1^3 \ e^(2x) \ dx`
`\ \ \ = [ \ e^(2x)/2 \ ]_1^3`
`\ \ \ = 1/2 (e^6-e^2)`
`\ \ \ = 198.019868 ...`