# Find the coordinates of the vertices and foci, eccentricity? #x^2-8x+2y+7=0#

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Find the coordinates of the vertices and foci, and the equations of the directrices and axes of the conic #x^2-8x+2y+7=0# . What is its eccentricity? Give a rough sketch of this conic.

Find the coordinates of the vertices and foci, and the equations of the directrices and axes of the conic

##### 1 Answer

Mar 11, 2017

#### Answer:

The vertex is

The focus is

The directrix is

The eccentricity of a parabola

#### Explanation:

Let's rewrite this equation and complete the squares

We compare this equation to

The vertex is

The focus is

The directrix is

The eccentricity of a parabola

graph{(x^2-8x+2y+7)(y-5)((x-4)^2+(y-4)^2-0.01)=0 [-16.02, 16.01, -8.01, 8.01]}