Question

For the given vector: v = 3i - j + 2k, how do you write a unit vector in the direction of vector v?

Answer 1

`v/(|| v ||) = 3/sqrt(15)i-1/sqrt(15)j+2/sqrt(15)k`

Explanation:

`|| v || = sqrt(3^2+(-1)^2+2^2) = sqrt(9+1+4) = sqrt(15)`

So the normalised vector in the direction of `v` is:

`v/(|| v ||) = 1/(sqrt(15)) (3i-j+2k) = 3/sqrt(15)i-1/sqrt(15)j+2/sqrt(15)k`