For the line with a slope,m, of -4/1 and passing through the point (1,-2), how do you write the equation in the slope intercept format?

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Answer 1 · 2016-06-03T19:46:55

The equation of the line in slope intercept form is
#y=-4/1x +2#

The slope-intercept format of the equation of the line is #y=mx+b#
Where #m=# the slope and #b=# the y-intercept.

Since we are given the slope, #m=-4/1# and a point (1,-2) we can plug these values in and solve for the y-intercept.

#x=1#
#y=-2#
#m=-4/1#

#y=mx+b#

#-2=-4/1 (1) + b#

#-2=-4 + b#

#-2 +4 = cancel(-4)cancel (+4) + b#

#2=b#

The equation of the line in slope intercept form is
#y=-4/1x +2#