Question

Given a Right Triangle with a base of 75 ft. and hypotenuse of 92.71 ft., find the length of the remaining leg, and the two remaining angles (in degrees)?

Answer 1

Length of remaining leg `= 54.5` ft Remaining angles are `54^0 and 36^0`

Explanation:

Length of remaining leg `= sqrt(92.71^2-75^2) = 54.5 ft`
Using sine laws in the triangle `92.71/sin 90 = 75/sin B or sin B=(75*1)/92.71 or /_B=54^0` So `/_C=180-90-54=36^0`