# Given a Right Triangle with a base of 75 ft. and hypotenuse of 92.71 ft., find the length of the remaining leg, and the two remaining angles (in degrees)?

Length of remaining leg $= 54.5$ ft Remaining angles are ${54}^{0} \mathmr{and} {36}^{0}$
Length of remaining leg $= \sqrt{{92.71}^{2} - {75}^{2}} = 54.5 f t$
Using sine laws in the triangle $\frac{92.71}{\sin} 90 = \frac{75}{\sin} B \mathmr{and} \sin B = \frac{75 \cdot 1}{92.71} \mathmr{and} \angle B = {54}^{0}$ So $\angle C = 180 - 90 - 54 = {36}^{0}$