Given #csctheta^circ=sqrt3/2# and #sectheta^circ=sqrt3/3#, how do you find #costheta#?

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Answer 1 · 2016-12-29T14:51:53

#costheta = sqrt(3)#

#sectheta = 1/costheta#

#sqrt(3)/3 = 1/costheta#

#costheta = 3/sqrt(3)#

Rationalize the denominator:

#costheta = (3sqrt3)/3#

#costheta = sqrt(3)#

Hopefully this helps!