Given $f(x)=6/x^2$ and $g(x)=x-3$ , how do you find g(f(x))?

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Answer 1 · 2016-01-30T17:02:03

To make a composition of a function you must plug one function into another, or on this case $f$ into g.

$f(x)$ = $6/x^2$

Plug in $f$ for x in g, since

g( $6/x^2$ ) = $6/x^2$ - 3

So, $g(f(x))$ = $6/x^2$ - 3

Practice exercises:

a) $f(g(x))$

b) $g(f(x))$

c) $f(g(-2))$

d). $g(f(7))$

Hopefully this helps.

Given f(x)=6/x^2f(x)=6/x^2 and g(x)=x-3g(x)=x-3, how do you find g(f(x))?