Given #f(x)=6/x^2# and #g(x)=x-3#, how do you find g(f(x))?

1 Answer
Noah G
Jan 30, 2016

To make a composition of a function you must plug one function into another, or on this case #f# into g.

Explanation:

#f(x)# = #6/x^2#

Plug in #f# for x in g, since

g(#6/x^2#) = #6/x^2# - 3

So, #g(f(x))# = #6/x^2# - 3

Practice exercises:

  1. Knowing that #f(x)# = #2x^2# + 15x + 22 and that #g(x)# = #-5/x#,
    find:

a) #f(g(x))#

b) #g(f(x))#

c) #f(g(-2))#

d). #g(f(7))#

Hopefully this helps.

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