# Given the equation (ax+b)(ax-b)=0, how do you solve for x?

Dec 21, 2016

$x = \pm \frac{b}{a}$

#### Explanation:

multiply out and rearrange for ""x

$\left(a x + b\right) \left(a x - b\right)$

this is difference of squares

${a}^{2} {x}^{2} - {b}^{2} = 0$

${a}^{2} {x}^{2} = {b}^{2}$

${x}^{2} = {b}^{2} / {a}^{2}$

x=+-sqrt(b^2/a^2

$x = \pm \frac{b}{a}$