# Given the point P(0.6, 0.8), how do you find sintheta and costheta?

Nov 23, 2016

Compute the r component of the polar coordinates, then use $y = r \sin \left(\theta\right) \mathmr{and} x = r \cos \left(\theta\right)$

#### Explanation:

Use the equation:

$r = \sqrt{{x}^{2} + {y}^{2}}$

$r = \sqrt{{0.6}^{2} + {0.8}^{2}}$

$r = \sqrt{0.36 + 0.64}$

r = 1

Use the equations $y = r \sin \left(\theta\right) \mathmr{and} x = r \cos \left(\theta\right)$

$0.8 = \left(1\right) \sin \left(\theta\right) \mathmr{and} 0.6 = \left(1\right) \cos \left(\theta\right)$

$\sin \left(\theta\right) = 0.8 \mathmr{and} \cos \left(\theta\right) = 0.6$