Given the point #P(0.6, 0.8)#, how do you find #sintheta# and #costheta#?

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Answer 1 · 2016-11-23T18:45:24

Compute the r component of the polar coordinates, then use #y = rsin(theta) and x = rcos(theta)#

Use the equation:

#r = sqrt(x^2 + y^2)#

#r = sqrt(0.6^2 + 0.8^2)#

#r = sqrt(0.36 + 0.64)#

r = 1

Use the equations #y = rsin(theta) and x = rcos(theta)#

#0.8 = (1)sin(theta) and 0.6 = (1)cos(theta)#

#sin(theta) = 0.8 and cos(theta) = 0.6#