Given the point #P(sqrt3/2,-1/2)#, how do you find #sintheta# and #costheta#?
2 Answers
Explanation:
Coordinate of P:
Since t is in Quadrant 4, then, sin t is negative
Since
Explanation:
In this problem we're only asked for
Students should recognize immediately The Two Tired Triangles of Trig. Trig mostly only uses two triangles, namely 30/60/90, whose sines and cosines in the various quadrants are
Two triangles for a whole course is really not that much to memorize. Rule of thumb:
None of that mattered for this particular problem so I'll end my rant here.