Gold has a density of $19.0$ $g$ $/$ $cm^3$ . What is the mass of a $3.0$ $mL$ sample of gold?

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Answer 1 · 2016-02-01T20:03:01

I found $57g$

We can use the fact that $3.0mL=3.0cm^3$ and that:
$"density"="mass"/"volume"$
in our case:
$19.0=m/3.0$
$m=3*19=57g$

Gold has a density of 19.019.0 gg//cm^3cm^3. What is the mass of a 3.03.0 mLmL sample of gold?