Graph the line with the slop 1/3 and y-intercept -2?

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Answer 1 · 2018-06-06T01:24:30

Please see below.

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The equation of a straight line is:

$y=mx+b$ where $m$ is the slope and $b$ is the $y$ -intercept.

Therefore, the equation for this line is:

$y=1/3x-2$

To graph it we can identify two points on the line and connect them together.

$x=0, :. y=-2$ this is the $y$ -intercept given in the problem.

$x=6, :. y=0$ this is the $x$ -intercept

Therefore, the two points are:

$(0,-2) and (6,0)$

Locate them on the coordinate system and connect them together.

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