# HCl is a strong acid. What is the pH of 100 mL of 0.003 M HCl?

$p H = 2.52$
$p H = - {\log}_{10} \left[{H}_{3} {O}^{+}\right]$ $=$ $- {\log}_{10} \left(3 \times {10}^{-} 3\right)$ $=$ $- \left(- 2.52\right)$.
The volume of the hydrochloric acid was included as a distractor. The concentration of $H C l$ was the vital information.