HCl is a strong acid. What is the pH of 200 mL of 0.002 M #HCl#?

1 Answer
Feb 6, 2017

Answer:

#pH=-log_10[H_3O^+]#

Explanation:

#"Hydrochloric acid"#, as a strong acid, is stoichiometric in #H_3O^+#. And thus:

#pH=-log_10[H_3O^+]=-log_10(0.002)=-(-2.70)=2.70#

Note that the #pH# thus depends on concentration solely. And thus what would be the #pH# of a #2*L# volume of #2xx10^-3*mol*L^-1# #"hydrochloric acid"#?