#"Hydrochloric acid"#, as a strong acid, is stoichiometric in #H_3O^+#. And thus:
#pH=-log_10[H_3O^+]=-log_10(0.002)=-(-2.70)=2.70#
Note that the #pH# thus depends on concentration solely. And thus what would be the #pH# of a #2*L# volume of #2xx10^-3*mol*L^-1##"hydrochloric acid"#?