Hector received a pay raise this year. The raise was 6% of last year's salary. This year he will earn $15,900. What was his salary last year before the raise?

1 Answer
May 29, 2018

Answer:

See a solution process below:

Explanation:

The formula for calculating a new salary is:

#n = p + (p * r)# Where:

#n# is the new salary: $15,900 for this problem.

#p# is the previous salary: what we are solving for in this problem.

#r# is the pay raise percentage: 6% for this problem. "Percent" or "%" means "out of 100" or "per 100", Therefore 6% can be written as #6/100#.

Substituting and solving for #p# gives:

#$15900 = p + (p * 6/100)#

#$15900 = p + (6p)/100#

#$15900 = 100/100p + 6/100p#

#$15900 = (100/100 + 6/100)p#

#$15900 = 106/100p#

#color(red)(100)/color(blue)(106) xx $15900 = color(red)(100)/color(blue)(106) xx 106/100p#

#($1590000)/color(blue)(106) = cancel(color(red)(100))/cancel(color(blue)(106)) xx color(blue)(cancel(color(black)(106)))/color(red)(cancel(color(black)(100)))p#

#$15000 = p#

#p = $15000#

Hector's salary last year before the raise was: #color(red)($15,000)#