Question

Help me please ??

1. Two kids pull in opposite directions on a toy of mass 0.544 kg. One exerts a force of 67.6 N and the other 12.6 N. Both pull horizontally and friction is negliglble.
   (f) Calculate the net force in the x-direction. (g) Calculate the normal force.
   (h) Calculate the net force in the y-direction.

Answer 1

From the free body diagram,we can say,

Net force acting horizontally, `(67.6-12.6)=55N` (along `X` axis)

As,the toy is not moving up or down,so it is at vertical equilibrium, So we can say `N=mg=0.544*10=5.44N` (`N` is the normal force)

So,net force along `Y` axis is zero.

Answer 2

55N, 0 or 5.33N, -5.33N or 0

Explanation:

Horizontal net force
`(f) F_"x net"= 67.6 -12.6 = 55N`.
The next force in the same direction of the stronger force.

`(g)` It depends. If the toy is not resting on anything, the normal force is zero. If it is resting on a desk or table while it is being pulled, then the desk pushes back with a normal force
`N- mg = 0, rArr N=mg =0.544 kg * 9.8 m/s^2=5.33N`

`(h)` If the toy is not resting on anything,

`F_"y net"=-mg = -5.33N`;

If the toy is resting on a desk, then `F_"ynet"= N-mg = 5.33N-5.33N=0`