# How do you find the vertex and the intercepts for #f(x)=x^2-x-12 #?

##### 1 Answer

May 8, 2018

**Vertex is at** **x intercepts are at**

**and y intercept is at**

#### Explanation:

equation

here

y intercept is found by putting

y intercept is at

x intercept is found by putting

x intercepts are at

graph{x^2-x-12 [-40, 40, -20, 20]} [Ans]