How can you evaluate #7/2-1/6-5/9+7/3#?

1 Answer
George C.
Jul 15, 2015

Choose a multiplier for each term to give them a common denominator, then add the numerators to get:

#7/2-1/6-5/9+7/3 = 63/18-3/18-10/18+42/18 = 92/18 = 46/9#

Explanation:

#7/2-1/6-5/9+7/3#

#=(9/9*7/2)-(3/3*1/6)-(2/2*5/9)+(6/6*7/3)#

#=63/18-3/18-10/18+42/18#

#=(63-3-10+42)/18 = 92/18 = 46/9#

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