# How do find the vertex and axis of symmetry, and intercepts for a quadratic equation y=x^2+2x-24?

x of vertex: $x = \left(- \frac{b}{2 a}\right) = - \frac{4}{2} = - 2$
To find x-intercepts, make $y = {x}^{2} + 2 x - 24 = 0.$Roots have different signs. Compose factor pairs of (-24) -> (-2, 12)(-4, 6). This sum is (6 - 4 = 2 = b). Then the 2 real roots are the opposites: 4 and -6.
two x-intercepts: $4 \mathmr{and} - 6$