How do find the vertex and axis of symmetry, and intercepts for a quadratic equation #y= -4x^2 + 3#?
1 Answer
Jul 17, 2015
y = -4x^2 + 3
Explanation:
x-coordinate of vertex: x = (-b/2a) = 0
y-coordinate of vertex: y = f(0) = 3
To find x intercept, make y = 0 -->
To find y intercept, make x = 0 --> y = 3
