Question

How do find the vertex and axis of symmetry, and intercepts for a quadratic equation `h(x)=-2(x-1)^2-3`?

Answer 1

h(x) = -2(x - 1)^2 - 3

Explanation:

x of vertex = x of symmetry axis = x = 1
y of vertex: y = -3
To get y-intercept, make x = 0 -> y = -2 -3 = -5
To get x-intercept, make h(x) = 0.
(x - 1)^2 = -3/2.
There are no x-intercepts. The parabola is completely below the x-axis. Its max. is the vertex (1, -3)