# How do find the vertex and axis of symmetry, and intercepts for a quadratic equation #f(x)=x^2+12x+36#?

##### 1 Answer

Jun 4, 2015

graph{x^2 + 12x + 36 [-10, 10, -5, 5]}

x-intercepts ->

x of vertex: x = -6

y of vertex: f(-6) = 36 - 72 + 36 = 0

Axis of symmetry: x = -6