Question

How do find the vertex and axis of symmetry for a quadratic equation `f(x) = -3x^2 - 6x - 2`?

Answer 1

`f(x) = -3x^2 - 6x - 2.`

Explanation:

x of vertex = x of axis of symmetry = `x = (-b/2a) = 6/-6 = - 1`

y of vertex = f(-1) = -3 + 6 - 2 = 1