# How do find the vertex and axis of symmetry for a quadratic equation f(x) = -3x^2 - 6x - 2?

$f \left(x\right) = - 3 {x}^{2} - 6 x - 2.$
x of vertex = x of axis of symmetry = $x = \left(- \frac{b}{2} a\right) = \frac{6}{-} 6 = - 1$