# How do find the vertex and axis of symmetry for a quadratic equation y = x^2+ 4x + 3?

x of vertex: $x = \left(- \frac{b}{2 a}\right) = - \frac{4}{2} = - 2$
x of the axis of symmetry: $x = \left(- \frac{b}{2 a}\right) = - 2$