Question

How do find the vertex and axis of symmetry for a quadratic equation `y = x^2+ 4x + 3`?

Answer 1

x of vertex: `x = (-b/(2a)) = -4/2 = -2`

y of vertex: y = f(-2) = 4 - 8 + 3 = -1

x of the axis of symmetry: `x = (-b/(2a)) = -2`