How do I convert the equation 9x^2−y^2+54x+10y+55=0 to standard form?

$a = \frac{1}{3} , b = 1 , h = - 3 , k = 5$
${\left(3 x + 9\right)}^{2} - 81 - {\left(y - 5\right)}^{2} + 25 = - 55$
$9 {\left(x + 3\right)}^{2} - {\left(y - 5\right)}^{2} = 1$
${\left(x - h\right)}^{2} / {a}^{2} - {\left(y - k\right)}^{2} / {b}^{2} = 1$