How do I find the derivative of $y = e^ln(x)$ ?

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Answer 1 · 2016-01-07T16:34:00

$dy/dx=1$

$y=e^(lnx)=x$ . (By properties of logs).

$therefore dy/dx=d/dx x = 1$ .

Alternatively, we may apply the derivative of the whole function before simplifying it and will get the same final answer :\

$d/dx e^(lnx)=e^(lnx)*1/x$

$=x*1/x$

$=1$ .

How do I find the derivative of y = e^ln(x)y = e^ln(x)?